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A business statistics professor at a college would like to develop a regression

ID: 3358685 • Letter: A

Question

A business statistics professor at a college would like to develop a regression model to predict the final scores for students based on their current GPAs, the number of hours they studied for pracitce, and the number of times they were absent during the semester. The data for these variables are in the accompanying table. Complete parts a through d below.

a. Construct a regression model using all three independent variables. Let y be the final exam scores,x1 be the GPAs,x2be the number of hours spent studying, and x3 be the number of absences during the semester.

Score

GPA

Hours

Absences

69

2.52

3.0          

0

70

2.26

4.0

3

70

2.60

2.5

1

71

3.09

0.5

0

74

3.08

6.0

4

77

2.76

3.5

7

77

3.35

1.5

0

77

2.99

3.0

3

77

2.98

2.0

3

80

2.85

2.5

2

78

2.80

4.5

0

81

3.44

7.0

1

82

3.25

3.0

1

84

3.15

3.0

4

84

3.16

5.5

0

83

2.95

2.0

0

85

2.70

4.0

1

86

3.20

4.5

3

86

3.76

2.0

0

85

3.55

3.5

2

86

2.93

6.0

1

85

3.03

6.5

1

86

3.16

5.0

3

86

3.89

7.5

4

88

3.53

4.0

0

88

3.31

6.5

1

90

3.67

5.0

0

89

2.88

3.5

1

91

3.39

6.0

1

91

3.21

4.5

2

91

3.80

7.0

0

91

3.93

6.0

2

92

3.99

5.0

0

91

3.58

6.5

1

92

2.98

4.0

2

94

3.27

6.5

0

97

2.88

3.5

0

98

3.73

5.0

1

100

3.48

6.5

1

101

3.02

7.0

0

Score     

GPA

Hours

Absences

ModifyingAbove y =(    ) + (    ) x1 +(    ) x2 + (    )x3

(Round to three decimal places as needed.)

b. Calculate the multiple coefficient of determination.

c. Test the significance of the overall regression model using =0.05

d. Calculate the adjusted multiple coefficient of determination

Score

GPA

Hours

Absences

69

2.52

3.0          

0

70

2.26

4.0

3

70

2.60

2.5

1

71

3.09

0.5

0

74

3.08

6.0

4

77

2.76

3.5

7

77

3.35

1.5

0

77

2.99

3.0

3

77

2.98

2.0

3

80

2.85

2.5

2

78

2.80

4.5

0

81

3.44

7.0

1

82

3.25

3.0

1

84

3.15

3.0

4

84

3.16

5.5

0

83

2.95

2.0

0

85

2.70

4.0

1

86

3.20

4.5

3

86

3.76

2.0

0

85

3.55

3.5

2

86

2.93

6.0

1

85

3.03

6.5

1

86

3.16

5.0

3

86

3.89

7.5

4

88

3.53

4.0

0

88

3.31

6.5

1

90

3.67

5.0

0

89

2.88

3.5

1

91

3.39

6.0

1

91

3.21

4.5

2

91

3.80

7.0

0

91

3.93

6.0

2

92

3.99

5.0

0

91

3.58

6.5

1

92

2.98

4.0

2

94

3.27

6.5

0

97

2.88

3.5

0

98

3.73

5.0

1

100

3.48

6.5

1

101

3.02

7.0

0

Score     

GPA

Hours

Absences

Explanation / Answer

Solution:

Required multiple regression model (by using excel) is given as below:

Regression Statistics

Multiple R

0.6833

R Square

0.4669

Adjusted R Square

0.4225

Standard Error

6.2059

Observations

40

ANOVA

df

SS

MS

F

P-value

Regression

3

1214.309

404.770

10.510

0.000

Residual

36

1386.466

38.513

Total

39

2600.775

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

55.802

8.289

6.732

0.000

38.992

72.613

GPA

7.047

2.717

2.594

0.014

1.537

12.556

Hours

1.842

0.606

3.038

0.004

0.612

3.072

Absences

-1.099

0.647

-1.699

0.098

-2.410

0.213

Part a

Required regression equation is given as below:

Y = 55.802 + 7.047*X1 + 1.842*X2 – 1.099*X3

Score = 55.802 + 7.047*GPA + 1.842*Hours – 1.099*Absences

Part b

Multiple coefficient of determination is given as below:

Coefficient of determination = R2 = R*R = 0.6833*0.6833 = 0.466899

Part c

We are given

Level of significance = = 0.05

P-value for overall regression model is given as below:

P-value = 0.00

P-value < = 0.05

So, we reject the null hypothesis that the given regression model is not statistically significant.

This means, there is sufficient evidence to conclude that given regression model is statistically significant. There is a significant linear relationship exists between the dependent variable score and set of independent variables such as GPA, Hours, and Absences.

Part d

The formula for adjusted multiple coefficient of determination is given as below:

R2adjusted = 1 – ( 1 – R2)*[(n – 1)/(n – (k + 1))]

Where, n is sample size and k is number of independent variables in regression model.

We are given

R2 = 0.466899

n = 40

k = 3

R2adjusted = 1 – ( 1 – 0.466899)*[(40 – 1)/(40 – (3 + 1))]

R2adjusted = 1 – 0.533101*[39/36]

R2adjusted = 1 – 0.533101* 1.083333

R2adjusted = 1 – 0.577526

R2adjusted = 0.422474

Regression Statistics

Multiple R

0.6833

R Square

0.4669

Adjusted R Square

0.4225

Standard Error

6.2059

Observations

40

ANOVA

df

SS

MS

F

P-value

Regression

3

1214.309

404.770

10.510

0.000

Residual

36

1386.466

38.513

Total

39

2600.775

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

55.802

8.289

6.732

0.000

38.992

72.613

GPA

7.047

2.717

2.594

0.014

1.537

12.556

Hours

1.842

0.606

3.038

0.004

0.612

3.072

Absences

-1.099

0.647

-1.699

0.098

-2.410

0.213