Given the following ANOVA table for three treatments each with six observations:

Question

Given the following ANOVA table for three treatments each with six observations:

Source

Sum of Squares

df

Mean square

Treatment

1116

Error

1068

Total

2184

What is the decision regarding the null hypothesis at the 5% significance level?

reject H0—there is a difference in treatment means.

Fail to reject H0—there is a difference in treatment means.

Reject H0—there is a difference in errors.

Fail to reject H0—there is a difference in errors.

Source

Sum of Squares

df

Mean square

Treatment

1116

Error

1068

Total

2184

Explanation / Answer

Ans:

k=3

n=6*3=18

dfn=k-1=3-1=2

dfd=n-k=18-3=15

Mean square=SS/df

F=MStreatment/MSerror=7.837

p-value=Fdist(7.837,2,15)=0.0047

Assume significance level=0.05

As,p-value=0.0047<0.05,we reject null hypothesis.

Reject H0—there is a difference in treatment means.

Source Sum of Squares df Mean square F p-value Treatment 1116 2 558 7.837 0.0047 Error 1068 15 71.2 Total 2184 17

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.