In a recent household telephone survey of 2,650 adults in a certain country, 28%

Question

In a recent household telephone survey of 2,650 adults in a certain country, 28% reported that they own at least one gun. The researchers want to estimate the true percentage of adults in that country that own at least one gun. Complete parts a through f below. a. Identify the population of interest to the researchers. Choose the correct answer below. A. The set of guns in the country B. The set of adults in the country that own a gun The set of adults that responded to the survey b. Identify the parameter of interest to the researchers. C. The set of all gun ownership status (yes/no) values for all adults in the country D. The parameter of interest is c. Compute an estimate of the population parameter (Type an integer or a decimal.) d. Form a 99% confidence interval around the estimate. (Round to two decimal places as needed.) e. Interpret the confidence interval practically. Choose the correct answer below. ( A. O B. ° C. There is a 99% probability that the true proportion of gun owners is the mean of the interval. One can be 99% confident the true proportion of gun owners lies at the mean of the above interval One can be 99% confident the true proportion of gun owners lies within the above interval. D. One can be 99% confident the true proportion of gun owners is one of the end points of the above interval f. Explain the meaning of the phrase "99% confident." Choose the correct answer below. 0 A. O B ° C. It means that 99% of the possible population proportions will fall into this confidence interval. t means that there is a 99% probability that the tre proportion o gun owners will be in the com ence interva or It means that 99% of all similarly formed intervals will contain the true proportion of gun owners in the country e rom the first sam taken.

Explanation / Answer

The statistical software output for this problem is:

One sample proportion summary confidence interval:
p : Proportion of successes
Method: Standard-Wald

99% confidence interval results:

Hence,

a) Option B is correct.

b) p

c) 0.28

d) 99% confidence interval:

( 0.26, 0.30)

e) Option B is correct.

f) Option C is correct.

Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit p 742 2650 0.28 0.0087221254 0.25753329 0.30246671

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