In a reaction between pure acetic acid and sodium bicarbonate, 28.0 grams of sod

Question

In a reaction between pure acetic acid and sodium bicarbonate, 28.0 grams of sodium bicarbonate was added to 12.0 mL of acetic acid. Which reactant is the limiting reactant in this reaction?

Name of limiting reactant (acetic acid or sodium bicarbonate):

How many moles of the limiting reactant are present in this reaction?

Moles of limiting reactant =   mol

How many moles of carbon dioxide do you expect to be produced?

Moles of carbon dioxide =  mol CO2

If the temperature in the laboratory is 24.3oC and the atmospheric pressure is 0.920 atm, what volume would be occupied by the carbon dioxide produced in this reaction (in cm3)?

Volume of carbon dioxide =   cm3

What would be the circumference of a spherical balloon containing this amount of carbon dioxide gas?

Circumference of balloon =   cm

Explanation / Answer

CH3COOH + NaHCO3 ----------> CH3COOna + H2O + CO2,

mol of sod bicarbonate = 28/84 = 0.333,

acetic acid moles = 12 x 1.05/60.05 = 0.21 ( where 1.05 = density ) ,

limiting reagent is acetic acid

moles of limiting reagent = 0.21 ,

moles of CO2 expected = 0.21,

V = nRT/P = 0.21 x0.0821 x (273+24.3)/0.92 = 5.57147 litres = 5571.47 cm3

V = (4/3) x3.14 x r^3

5571.47 = ( 4/3) x3.14 xr^3

r = 10.999 = 11 cm

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