Question Help A clinical trial was conducted using a new method designed to incr

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Question Help A clinical trial was conducted using a new method designed to increase the probability of conceiving a girl As of this writing. 937 babies and 864 of them were giris. Use a 0.05 significance level to test null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P.value method and the normal distribution as an approximation to the binomial distribution t the claim that the new method is effective in increasing the likelihood that a baby will be a girt. Identify the were born to parents using the new method What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value tn four dorimal nlaroc ae Click to select your answer(s).

Explanation / Answer

Given that,
possibile chances (x)=864
sample size(n)=937
success rate ( p )= x/n = 0.9221
success probability,( po )=0.5
failure probability,( qo) = 0.5
null, Ho:p=0.5  
alternate, H1: p>0.5
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.64
since our test is right-tailed
reject Ho, if zo > 1.64
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.92209-0.5/(sqrt(0.25)/937)
zo =25.8408
| zo | =25.8408
critical value
the value of |z | at los 0.05% is 1.64
we got |zo| =25.841 & | z | =1.64
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail - Ha : ( p > 25.84084 ) = 0
hence value of p0.05 > 0,here we reject Ho
ANSWERS
---------------
test statistic: 25.84
p-value: 0

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