Question Help A company announced a 1000 Chips Trial,\" claiming that every 18-o

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Question Help A company announced a 1000 Chips Trial," claiming that every 18-ounce bag of its cookies contained at least 1000 chocclate chips. Students purchased random bags of cookies from different stores and counted the number of chips in each bag. Some of the data is shown below. Complete parts (a) through (c) below. 1076 1269 1108 1278 1189 1368 1284 1378 1201 1463 a) Check the assumptions and conditions for inference. Check the data for independence. Choose the correct answer below. O A. The data are from a random sample, so one can assume that they are not independent. O B. The sample is less than 10% of the population, so one can assume that the data are not independent. O C. The data are from a random sample, so one can assume that they are independent. O D. The sample is less than 10% of the population, so one can assume that the data are independent. Construct a histogram of the data. Choose the correct graph below. OA. B. 900 Chips Evaluate the histogram. Choose the correct answer below. O A. The histogram is roughly unimodal and asymmetric, so one can assume that the data come from a population that follows a t-Student's model. O B. The histogram is roughly unimodal and symmetric, with no outliers, so one can assume that the data come from a population that follows a Normal model ? C. The histogram is roughly bimodal and symmetric, with no outliers, so one can assume that the data come from a population that follows a Normal model. ( D. The histogram is roughly bimodal and asymmetric, so one can assume that the data come from a population that follows a t-Student's model.

Explanation / Answer

a)
The assumption for independence is,
C. The data are from a random sample, so one can assume that they are independent.

The correct histogram is B.

Based on Histogram B,
B. The histogram is roughly unimodal and symmetric, with no outliers, so one can assume that the data come from a population that follows a Normal model.

b)
The mean number of chips is 1261.4
The standard deviation of number of chips is 121.6736984
Standard error of mean number of chips = sd / sqrt(n) = 121.6736984 / sqrt(10) = 38.47660183
Z value for 95% confidence interval is 1.96
Margin of error = Z * Standard error = 1.96 * 38.47660183 = 75.41413959

95% confidence interval is
(Mean - Margin of error, Mean + Margin of error)
(1261.4 - 75.41413959, 1261.4 + 75.41413959)
(1186.0, 1336.8)

c)

As, the 95% confidence interval lower limit is greater than the value of 1000,
D. Because the confidence interval is entirely above 1000, the mean number of chips per bag is likely more than 1000. However, the Normal model predicts that a small amount of individual bags will have fewer than 1000 chips.

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