Significance level H1 0.01 0.05 0.02 0.01 Left Tailed –1.282 –1.645 –2.054 –2.32
ID: 3359437 • Letter: S
Question
Significance level
H1
0.01
0.05
0.02
0.01
Left Tailed
–1.282
–1.645
–2.054
–2.326
Right Tailed
1.282
1.645
2.054
2.326
Two Tailed
±1.645
±2.326
±2.326
±2.576
One of your pizza delivery boys claims that his on-time pizza delivery record is greater than all the other pizza delivery persons working for your restaurant. As you may recall 97% of your pizza deliveries are being made in 30 minutes or less. So to test the delivery boy’s claim you take a random sample of 344 of his deliveries and note that 339 of the deliveries were made on time. Use = 0.05 level of significance.
What is the null and alternative hypothesis?
Should a two-tailed, right-tailed, or left-tailed test be performed?
Calculate the test statistic (Use 1-PropZTest on the TI Calculator and remember the test statistic is z)
Round 3 decimals
Look up the critical z-values for = 0.05 (See Table on Guided Notes)
Draw a normal curve that depicts the critical region. Label your test statistic and the critical value on the diagram.
Is the test statistic in the critical region?
What is the result of the test? (Reject H0 or Do Not Reject H0)
State the conclusion.
Should you give this pizza delivery boy an award for pizza delivery person of the year? Explain why or why not.
Significance level
H1
0.01
0.05
0.02
0.01
Left Tailed
–1.282
–1.645
–2.054
–2.326
Right Tailed
1.282
1.645
2.054
2.326
Two Tailed
±1.645
±2.326
±2.326
±2.576
Explanation / Answer
Given that,
possibile chances (x)=334
sample size(n)=339
success rate ( p )= x/n = 0.9853
success probability,( po )=0.97
failure probability,( qo) = 0.03
null, Ho:p=0.97
alternate, H1: p>0.97
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.64
since our test is right-tailed
reject Ho, if zo > 1.64
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.98525-0.97/(sqrt(0.0291)/339)
zo =1.6461
| zo | =1.6461
critical value
the value of |z | at los 0.05% is 1.64
we got |zo| =1.646 & | z | =1.64
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail - Ha : ( p > 1.64605 ) = 0.04988
hence value of p0.05 > 0.04988,here we reject Ho
ANSWERS
---------------
null, Ho:p=0.97
alternate, H1: p>0.97
one tailed, right
test statistic: 1.6461
critical value: 1.64
decision: reject Ho
p-value: 0.04988
delivery boys claims that his on-time pizza delivery record is greater than
all the other pizza delivery persons working for your restaurant.
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