2. 0/3 points I Previous Answers MintroStat8 7.E.506.XP My Notes Ask Your Teache

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2. 0/3 points I Previous Answers MintroStat8 7.E.506.XP My Notes Ask Your Teacher Assume X1 = 98, X2 = 119, s1 = 9, s2 = 1 1, n1 = 50, and n2 = 50. Find a 95% confidence interval for the difference in the corresponding values of . (Round your answers to three decimal places.) Does this interval include more or fewer values than a 99% confidence interval? Explain your answer This interval includes fewer values because a smaller confidencelvel means that we need a smaller margin of error. This interval includes fewer values because a smaller confidence level means that we need a larger margin of error O This interval includes more values because a smaller confidence level means that we need a smaller margin of erro This interval includes more values because a smaller confidence level means that we need a larger margin of error Submit Answer

Explanation / Answer

mean = x2-x1

= 119 - 98

= 21

standard devation = sqrt ( 9^2/50 + 11^2/50)

= sqrt(101)/5

margin of error = 1.96 * sqrt(101)/5 = 3.93955

lower bound = 21 - 3.93955 = 17.061

upper bound = 21 + 3.93955 = 24.940

interval includes fewer values because smaller confidence level means we need a small margin of error

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