Suppose that the scores of golfers on the PGA tour have a mean of 73.6 and a sta

Question

Suppose that the scores of golfers on the PGA tour have a mean of 73.6 and a standard deviation of 3.2. A random sample of 41 is taken from the population. What is the distribution of the sample mean?

Question 3 options:

1)

2)

3)

4)

5)

1)

Approximately normal with mean 73.6 and standard error 3.2.

2)

73.6 give or take 3.2.

3)

Approximately normal with mean 73.6 and standard error 0.5.

4)

Approximately normal with mean 11.49 and standard error 0.5.

5)

68% of sample averages will fall between 70.4 and 76.8.

Explanation / Answer

Mean is 73.6 and s is 3.2

the sample size is of 41 and therefore the standard error, SE is s/sqrt(N)=3.2/sqrt(41)=0.4998

thus Approximately normal with mean 73.6 and standard error 0.5. option 3) is correct

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