Suppose you knew that the heights of adult males in the US is normally distribut

Question

Suppose you knew that the heights of adult males in the US is normally distributed with a mean of 69.8 inches and a standard deviation of 1.5 inches. How would you find the probability that an adult male chosen at random would have a height between 70 and 72 inches?

Find the Z score for 70 inches and 72 inches and calculate the area under the standard normal curve between these two Z scores.

Find the Z score for 68 inches and calculate the area under the standard normal curve from the mean to that Z score then add the area from the mean to 72 inches.

Find the Z score for 70 inches and calculate the area under the standard normal curve from the mean to that Z score and add 0.5

Find the Z score for 70 inches and calculate the area under the standard normal curve to the left of that Z score for 72 inches.

Find the Z score for 70 inches and 72 inches and calculate the area under the standard normal curve between these two Z scores.

Find the Z score for 68 inches and calculate the area under the standard normal curve from the mean to that Z score then add the area from the mean to 72 inches.

Find the Z score for 70 inches and calculate the area under the standard normal curve from the mean to that Z score and add 0.5

Find the Z score for 70 inches and calculate the area under the standard normal curve to the left of that Z score for 72 inches.

Explanation / Answer

Mean is 69.8 and s is 1.5

P(70<x<72)=P(x<72)-P(x<70)

A. Find the Z score for 70 inches and 72 inches and calculate the area under the standard normal curve between these two Z scores is thus correct

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