Assume that a sample is used to estimate a population proportion p . Find the ma

Question

Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 323 with 79.9% successes at a confidence level of 99.9%.

M.E. = % Round to 4 places.

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Assume that a sample is used to estimate a population proportion p. Find the margin of error ME that corresponds to a sample of size 323 with 79.9% successes at a confidence level of 99.9%. % Round to 4 places. Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Explanation / Answer

P = 0.799

At 99.9% confidence interval the critical value is 3.27

Margin of error = z* * sqrt(P * (1 - P)/n)

= 3.27 * sqrt(0.799 * 0.201/323)

= 0.0729 = 7.29%

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.