126f 18(15 complete) This Quiz: 18 pts possible This Question: 1 pt Twelve diffe

Question

126f 18(15 complete) This Quiz: 18 pts possible This Question: 1 pt Twelve different video games showing substance use were observed and the duration times of game play (in seconds) are listed below. The design of the study justifies the assumption that te sample can be treated as a simple random sample. Use the data to construct a 95% confidence interval estimate of , the mean duration of game play 4059 3874 3852 4022 4314 4812 4649 4036 5004 4830 4336 4315 Click here to view a t distribution table Click here to view page 1 of the standard normal distribution table what is the confidence interval estimate of the population mean ? Round to one decimal place as needed.)

Explanation / Answer

Mean = (4059 + 3874 + 3852 + 4022 + 4314 + 4812 + 4649 + 4036 + 5004 + 4830 + 4336 + 4315)/12 = 4341.92

Variance = ((4059 - 4351.92) + (3874 - 4341.92) + (3852 - 4341.92) + (4022 - 4341.92) + (4314 - 4341.92)+ (4812 - 4341.92) + ( 4649 - 5351.92) + (4036 - 4341.92)+ (5004 - 4341.92) + (4830 - 4341.92) + (4336 - 4341.92)+( 4315 - 4341.92)/11 = 157120

Standard deviation = sqrt(157120) = 396.38

DF = 12 - 1 =11

With 11 degrees of freedom and 95% confidence interval the critical value is 2.201

Confidence interval is

Mean +/- t* * SD/sqrt (n)

= 4341.92 +/- 2.201 * 396.38/sqrt (12)

= 4341.92 +/- 251.85

= 4090.07, 4593.77

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.