Complete: Chapter 15 Problem Set e Due Today 1159 PM EST Now, using the volues f

Question

Complete: Chapter 15 Problem Set e Due Today 1159 PM EST Now, using the volues for the meons that you just calculated, fill out the folowing table by calculating the deviations from the means for X and Y, the squares of the deviatons, and the products of the deviations Average: 17 Attempts 4. Scatter plots and calculating correlation Suppose you are given the following five pairs of scores: Aa Aa Products XY 105 9 10 The sum of squared deviations for x is ss,= ofproducts is SP=-29 38 "The sum of squared deviations for Y is SS-40 . The sum - . " Create a scatter plot of these scores in the following diagram, For each of the five (X, Y) pairs, cick on the plotting symbal (the black X) in the upper right comer of the tool, and drag it to the appropriate location on the grid. Because the sign of the sum of products is positivethe sign of the Pearson correlation will be The Pearson correlation is r- 0.74 Lock at your scatter plot again. If you excluded the point (9, 10), you would expect the recalculated Pearson correlation to be dfterent correlation is not the same as causation the relationship between X and Y is noninear (9, 10) is an outlier Based on your scatter plot, you would expect the correlation to be negative The mean X sore is MK-4 , and the mean Y score is MY- 5 . Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations.

Explanation / Answer

All your calculations are correct

Mx = 20/5 = 4

My = 25/5 = 5

you would expect recalculated Pearson correlation is different because X and Y are correlated

X Y X - Mx Y - MY (X - Mx)2 (Y-MY)2 (X - Mx)(Y-MY) 4 2 0 -3 0 9 0 1 3 -3 -2 9 4 6 4 4 0 -1 0 1 0 2 6 -2 1 4 1 -2 9 10 5 5 25 25 25

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