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5) A test consists of 20 multiple choice questions, each with five possible answ

ID: 3364947 • Letter: 5

Question

5) A test consists of 20 multiple choice questions, each with five possible answers, only one of which is correct. Find the mean and the standard deviation of the number of correct answers. A) mean: 10; standard deviation: 1.79 C) mean: 10; standard deviation: 3.16 B) mean: 4; standard deviation: 2 D) mean: 4; standard deviation: 1.79 6) A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the student guesses on each question, what is the probability that the studer will pass the test? A) 0.055 B) 0.08 C) 0.20 D)0.8 Find the area under the standard normal curve between z =-1.5 and z = 25. A) 0.7182 B) 0.9831 C) 0.9270 D) 0.6312

Explanation / Answer

5.

BIONOMIAL DISTRIBUTION

pmf of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k

where

k = number of successes in trials   

n = is the number of independent trials   

p = probability of success on each trial

I.

mean = np

where

n = total number of repetitions experiment is excueted

p = success probability

mean = 20 * 0.2

= 4

II.

variance = npq

where

n = total number of repetitions experiment is excueted

p = success probability

q = failure probability

variance = 20 * 0.2 * 0.8

= 3.2

III.

standard deviation = sqrt( variance ) = sqrt(3.2)

=1.7889

= 1.79

6.

BIONOMIAL DISTRIBUTION

pmf of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k

where

k = number of successes in trials   

n = is the number of independent trials   

p = probability of success on each trial

I.

mean = np

where

n = total number of repetitions experiment is excueted

p = success probability

mean = 10 * 0.5

= 5

II.

variance = npq

where

n = total number of repetitions experiment is excueted

p = success probability

q = failure probability

variance = 10 * 0.5 * 0.5

= 2.5

III.

standard deviation = sqrt( variance ) = sqrt(2.5)

=1.5811

P( X < 8) = P(X=7) + P(X=6) + P(X=5) + P(X=4) + P(X=3) + P(X=2) + P(X=1) + P(X=0)   

= ( 10 7 ) * 0.5^7 * ( 1- 0.5 ) ^3 + ( 10 6 ) * 0.5^6 * ( 1- 0.5 ) ^4 + ( 10 5 ) * 0.5^5 * ( 1- 0.5 ) ^5 + ( 10 4 ) * 0.5^4 * ( 1- 0.5 ) ^6 + ( 10 3 ) * 0.5^3 * ( 1- 0.5 ) ^7 + ( 10 2 ) * 0.5^2 * ( 1- 0.5 ) ^8 + ( 10 1 ) * 0.5^1 * ( 1- 0.5 ) ^9 + ( 10 0 ) * 0.5^0 * ( 1- 0.5 ) ^10

= 0.9453

P( X > = 8 ) = 1 - P( X < 8) = 0.0547 = 0.055

Area between normal curve Z=-1.5 and Z = 2.5

To find P(a < = Z < = b) = F(b) - F(a)

p(-1.5<z<2.5) = P(z<2.5)-p(Z<-1.5)

= 0.99397- 0.066807

= 0.926983 = 0.927

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