Lock, Statistics: Unlocking the Power of Data, 2e Grace Period: 1 days left l Re

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Lock, Statistics: Unlocking the Power of Data, 2e Grace Period: 1 days left l Register Now PRINTER VERSION4 BACK NEXT ASSIGNMENT RESOURCES Chapter 2, Section 6, Exercise 220 Sum18 Assignment 3 Predicting Percent Body Fat This problem uses the dataset BodyFat, which gives the percent of weight made up of body fat for 100 men as well as other variables such as Age, Weight (in pounds), Height (in inches), and circumference (in cm) measurements for the Neck, Chest, Abdomen, Ankle, Biceps, and Wrist.1 Using Abdomen Circurnference to Predict Body Fat Figure 1 shows the data and regression line for using weight to predict body fat percentage Chapter 2, Section 6, Figure 2 shows the data and regression line for using abdomen circumference to predict body fat percentage. hapter 2, Se Chapter P, Section 1, Chapter P. Scction 1 30 Chapter P, Section 1, Chapter P, Section1 Chapter P, Section 3, 10 120 140 160 180 200 220 240 260 280 Weight 70 80 100 110 120 130 Obigctive Figure 1 Using weight to predict percent body fat Figure 2 Using abdomen circumference to predict percent body fat Click here for the dataset associated with this question "A sample taken from data provided by R. Johnson in .Fitting Percentage of Body Fat to Simple Body Measurements," Journal of Statistics Education, ?1996), http://www.amstat.org/publications/ise/v4n1/datasets.johnson.html. (a) Which scatterplot, the one using Weight in Figure 1 or the one using Abdomen in Figure 2, appears to contain data with a larger correlation?

Explanation / Answer

a) The scatterplot of the abdomen contains dataset with more correlation. (As correlation measure the linear dependency)

b) From the scatter plot(as you don't provide the data), observed body fat corresponding to 127 cm abdomen circumference is, near about 34% or 35%.

The predicted body fat corresponding to 127cm abdomen circumference is, near about 40%.

c) Observed abdomen circumference corresponding to 40% body fat is near about 112 cm and the predicted abdomen circumference is near about 127cm. So, the residual is (112 - 127) = -15. If you take the absolute value of residual then the percentage will be = 15*100/112 % = 13%.

Note: As you didn't provide the data I have just given you rough estimates from the scatter plot.

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