of the second hat the trse iv) we do not have sufficient evidence that the true
ID: 3367028 • Letter: O
Question
of the second hat the trse iv) we do not have sufficient evidence that the true treatment means o eore nd aer resment are sigicanty aiterent we can rejest the claim that twe population variances are different we can spport the claim that w support the claim that s v) none ef these v) none of these p14 tr there are several wnblased ethnaten fora paremeter ? . Then the best estimator among them Is noe largest sample size. K, the smallest varince ?normal distribution· h) the largest variance. V) none of the these. Eehution wi vi- an 2-12 degs of rooloms Then the Sth perconaitle ertime har ts, the dime ,to th P95computed asing an appropriate provided 121Surpose the lfetme, N, of certaln mlcroprecessor (in years) has an F aMe is approx ? 2.850 noas0 v) 0.850 v) none of these strokes. f X denotes the mumber of mistakes in S0 iv) Negative Binomiale-- v) Poisson G vi) Bernoulli ( ) 2la the mumber ef D/3 15)33150s/ 4543/3 none of hese 0 0.500 ) 1.331 iii) 5300 iv) 7.000 v) none of abo ve D 0.333 0 0.4 iii) 0666 iv) nor s of these distribution (chat is the pointxo Jor which P(ksxo)-e05s equal to: D 569.35 n) 578.80 ii) 470.65 iv) 494.00 v) none of these specifications. An examination of n-80 randomly selected vans from the s anufacturers show rooms of heir popular vans, p, that new gExplanation / Answer
(a)
Since confidence interval does not conatin zero and all values are negative so we can conclude that response is signficantly lower after treatment.
option (ii) is correct.
(b)
Since confidence interval does not contain 1 so we can not conclude that population variances are equal.
option (iii) is correct.
(c)
Since p-value is less than 0.05 so we reject the null hypothesis.
option (iii) is correct.
(d)
option (ii) is correct.
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