13.) Eighty two percent of drivers carry jumper cables in their vehicles. For a

Question

13.) Eighty two percent of drivers carry jumper cables in their vehicles. For a random sample of 200 drivers, Binomial Distributions (page 205-206 (Show how you get these either by formula or calculator) a.) What is the probability that exactly 150 carry jumper cables in their vehicle? b.) What is the probability that at most 168 carry jumper cables in their vehicle? c.) What is the probability that more than 155 carry jumper cables in their vehicle? d.) What is the mean value of the number of drivers that carry jumper cables in their vehicle? e.) What is the standard deviation? 14.) The number of school related extracurricular activities per student are given below: p(x) 0.059 0.122 0.163 0.213 0.128 0.084 0.053 4 Suppose that a week is randomly selected. Using the above table, find a.) p(x-3) b.) p(x 22) c.)pxs7) d.) p(2srs5) 15.) The age and number of days after arthroscopic shoulder surgery before being able to return to their sport is given for 9 athletes. DAYS (y) 6

Explanation / Answer

Solution:-

13) Given that p = 0.82, n = 200

a) P(X = 150) = 0.0031

b) P(X <= 168) = 0.7945

c) P(X > 155) = 0.9382

d) mean = n*p = 200*0.82 = 164

e) standard deviation = sqrt(n*p*q) = sqrt(200*0.82*0.18) = 5.4332

14)
a) P(x = 3) = 1-(0.059+0.122+0.163+0.213+0.128+0.084+0.053) = 0.178

b) P(x >= 2) = 0.163+0.178+0.213+0.128+0.084+0.053 = 0.819

c) P(x <= 7) = 0.059+0.122+0.163+0.178+0.213+0.128+0.084+0.053 = 1

d)P(2 <= x <= 5) = 0.163+0.178+0.213+0.128 = 0.682

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