Need Help? Rad It 12 O1 points BBUnderStat12 6.5.022 Notes Ask Your Teacher The

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Need Help? Rad It 12 O1 points BBUnderStat12 6.5.022 Notes Ask Your Teacher The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.5 minutes and a standard deviation of 3.2 minutes. Assume that the distribution of taxi and takeoff times is approximately normal. You may assume that the jets are lined up on a runway so that one taxies and takes off immediately after the other, and that they take off one at a time on a given runway (a) What is the probability that for 33 jets on a given runway, total taxi and takeof time will be minutes? (Round your answer to four decimal places.) (b) What is the probability that for 33 jets on a given runway, total taxi and takeoff time will be more than 275 minutes? (Round your answer to four decimal places.) (c) What is the probability that for 33 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes? (Round your answer to four decimal places.) Need Help? Resdit Submit Answer Save Progress Practice Another Version My Notes?. Ask Your Te 13. Previous Answers BBUnderStat12 6.5 023 0/1 points It's true - sand dunes in Colorado rival sand dunes of the Great Sahara Desert! The highest dunes at Great Sand Dunes National Monument can exceed the highest dunes in the Great Sahara, extending over 700 feet in height. However, like all sand dunes, they tend to move around in the wind. This can cause a bit of trouble for temporary structures located near the

Explanation / Answer

Solution:- Given mean = 8.5 min, standard deviation = 3.2

For n = 33 x = 320/33 = 9.7
(a) P(x < 9.7) = P((x-?)/(?/sqrt(n) < (9.7 - 8.5)/(3.2/sqrt(33))
= P(Z > 2.1542)
= 0.9842

(b) x = 275/33 = 8.3
P(x > 8.3) = P((x-?)/(?/sqrt(n) > (8.3 - 8.5)/(3.2/sqrt(33))
= P(Z > -0.3590)
= 0.6406

(c) P(8.3 < x < 9.7) = P(-0.3590 < x < 2.1542) = 0.6248

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