spent an a erage of pi on a me at a rech rant Assume that te amount spent on a r

Question

spent an a erage of pi on a me at a rech rant Assume that te amount spent on a resturant meal is normally dett uted and that the standard deviation is $0. Complete One year parts (a) through (c) below a What is the probabiaty that a randomly selected person spent more than $26 P(X > $26)=?(Round to four decanal places as needed ) b. What is the probability that a randomly selected person spent between $8 and $23? P8-xs Round to tour decimal places as needed) c Between what two values will the middle 95% of the amounts of cash spent fall? 1 and X s4D The midde 95% of the amounts of cash spent wil fall between x-s (Round to the nearest cent as needed )

Explanation / Answer

Ans:

Given that

mean=24,standard deviation=6

a)

z=(26-24)/6=0.333

P(z>0.333)=0.3694

b)

z(8)=(8-24)/6=-2.667

z(23)=(23-24)/6=-0.167

P(-2.667<z<-0.167)=P(z<-2.667)-P(z<-0.167)

=0.4338-0.0038=0.4300

c)

z value for middle 95% cut off is 1.96

lower limit=24-1.96*6=12.24

upper limit=24+1.96*6=35.76

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