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I have a question:style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">

A model for the density Delta of the earth's atmosphere near its surface isstyle="font-size: 9pt; font-family: times;" data-mce-style="font-size: 9pt; font-family: times;">style="font-size: 9pt; font-family: mathematicalpi;" data-mce-style="font-size: 9pt; font-family: mathematicalpi;">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">

Delta = 619.09 - 0.000097rhostyle="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">style="font-size: 9.000000pt; font-family: 'mathematicalpi'" data-mce-style="font-size: 9.000000pt; font-family: 'mathematicalpi';">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">style="font-size: 9.000000pt; font-family: 'mathematicalpi'" data-mce-style="font-size: 9.000000pt; font-family: 'mathematicalpi';">style="font-size: 9.000000pt; font-family: 'mathematicalpi'" data-mce-style="font-size: 9.000000pt; font-family: 'mathematicalpi';">

where rho (the distance from the center of the earth) is measured in meters and Delta is measured in kilograms per cubic meter. If we take the surface of the earth to be a sphere with radius 6370 km, then this model is a reasonable one for
6.370*10^6 <= rho<= 6.375*10^6. data-mce-style="font-size: 9pt; font-family: times;">face="mathematicalpi" data-mce-style="font-family: mathematicalpi;">style="font-size: 9pt;" data-mce-style="font-size: 9pt; font-family: times;">style="font-size: 9pt; font-family: times;" data-mce-style="font-size: 9pt; font-family: times;">style="font-size: 9pt; font-family: mathematicalpi;" data-mce-style="font-size: 9pt; font-family: mathematicalpi;">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">style="font-size: 9.000000pt; font-family: 'mathematicalpi'" data-mce-style="font-size: 9.000000pt; font-family: 'mathematicalpi';">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">style="font-size: 9.000000pt; font-family: 'mathematicalpi'" data-mce-style="font-size: 9.000000pt; font-family: 'mathematicalpi';">style="font-size: 9.000000pt; font-family: 'times'" data-mce-style="font-size: 9.000000pt; font-family: 'times';">

Use this model to estimate the mass of the atmosphere between the ground and an altitude of 5 km. data-mce-style="font-size: 9pt; font-family: times;">

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From Stewart Calculus: Early Transcendentals 7E Ch15.9 Triple Integrals in Spherical Coordinates #42style="font-size: 9pt; font-family: times;" data-mce-style="font-size: 9pt; font-family: times;">

Explanation / Answer

Mass corresponds to weight.

Density is weight/volume.

(Example: 1 cubic foot of iron is heavier than

1 cubic foot of plastic foam).

specifies that weight (mass) is the issue.

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