Directions: Use the Crosstabs option in the Descriptives menu to answer the ques

Question

Directions: Use the Crosstabs option in the Descriptives menu to answer the questions based on the following scenario. (Be sure to select Chi-square from the Statistics submenu and Observed, Expected, Row, and Column in the Cells submenu. Assume a level of significance of .05) The school district recently adopted the use of e-textbooks, and the superintendent is interested in determining the level of satisfaction with e-textbooks among students and if there is a relationship between the level of satisfaction and student classification. The superintendent selected a sample of students from one high school and asked them how satisfied they were with the use of e-textbooks. The data that were collected are presented in the following table.
Satisfied Student Classification (N = 128)

1. Of the students that were satisfied, what percent were Freshmen, Sophomore, Junior, and Senior? (Round your final answer to 1 decimal place).
2. State an appropriate null hypothesis for this analysis.
3. What is the value of the chi-square statistic?
4. What are the reported degrees of freedom?
5. What is the reported level of significance?
6. Based on the results of the chi-square test of independence, is there an association between e-textbook satisfaction and academic classification?
7. Present the results as they might appear in an article. This must include a table and narrative statement that reports and interprets the results of the analysis.

Statisfied Freshmen Sophomore Junior Senior Yes 23 21 15 8 No 8 4 15 24

Explanation / Answer

1. Percentage Freshman = 23/(23 + 21 + 15 + 8) = 0.343= 34.3%

Precentage Sophomore = 21/(23 + 21 + 15 + 8) = 0.313 = 31.3%

Percentage junior = 15/(23 + 21 + 15 + 8) = 0.224 = 22.4$

Percentage Senior = 8/(23 + 21 + 15 + 8) = 0.119 = 11.9%

(2) Here Null Hypothesis is

H0 : Here student satisfaction and the year in which he/she is studying is independent of each other.

(3) Here observed table is given below

Expected table

Chi - square statistic

Here Degree of freedom = (4 -1) * (2 -1) = 3

Level of significane = 0.05

Here Critical value of chi - square

X2critical = 7.814

so here X2 < X2critical so we will reject the null hypotheisis and concludes that there is significant asscoaition between e- textbook satisfaction and academic classifaction.

Satisfied Freshmen Sophomore Junior Senior Total Yes 23 21 15 8 67 No 8 4 15 24 51 Total 31 25 30 32 118

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