The following data on price ($) and the overall score for 6 stereo headphones th

Question

The following data on price ($) and the overall score for 6 stereo headphones that were tested by Consumer Reports were as follows.

a. Does the t test indicate a significant relationship between price and the overall score?

The test t-Conclusion at ? = .05

t =  (to 2 decimal places.)

p-value is - Select your answer

1.-less than .02

2. between .02 and .05

3. between .05 and .1

4.between .1 and .2

5. greater than .2Item 2

What is your conclusion? Use ? = .05.
- Select your answer -

1. There is a significant relationship between price and overall score

2. There is no significant relationship between price and overall scoreItem 3 .

b. Test for a significant relationship using the F test.
p-value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .1greater than .1Item 4

What is your conclusion? Use ? = .05.

Because p-value is - Select your answer

-greater than or equal to

less than or equal to

equal to.05, we - Select your answer -

accept

reject H0: ?1 is - Select your answer -greater than or equal to zero

less than or equal to zero

equal to zero.

c. Show the ANOVA table for these data. Round your answers to three decimal places, if necessary.

Brand Price Score Bose 190 76 Scullcandy 160 74 Koss 85 63 Phillips/O'Neill 70 58 Denon 80 40 JVC 35 26

Explanation / Answer

a.

Pearson correlation of Price and Score = 0.859
P-Value = 0.028

Ans: 2. between .02 and .05

Since p-value=0.028<0.05 so there is a significant relationship between price and overall score at 0.05 level.

Ans. 1. There is a significant relationship between price and overall score.

b.

Analysis of Variance

Source DF SS MS F P
Regression 1 12840 12840 11.30 0.028 (between .025 and .05)
Residual Error 4 4544 1136
Total 5 17383

p-value is - between .025 and .05.

So there is significant relationship between price and score.

Regression Analysis: Price versus Score

The regression equation is
Price = - 41.4 + 2.58 Score

Predictor Coef SE Coef T P
Constant -41.43 45.20 -0.92 0.411
Score 2.5774 0.7666 3.36 0.028

Because p-value i.e. 0.028 is- less than 0.05 so we reject H0:?1=0

c. Analysis of Variance

Source DF SS MS F P
Regression 1 12840 12840 11.30 0.028 (between .025 and .05)
Residual Error 4 4544 1136
Total 5 17383

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