Public Policy and Political Science. Recent national elections suggest that the
ID: 3376807 • Letter: P
Question
Public Policy and Political Science. Recent national elections suggest that the political ideology of adults in the United States is very evenly divided. In a USA Today/Gallup survey, 29% were Republicans, 30% were Democrats, and 41% were Independents. In addition, 51% of all Republicans, 16% of all Democrats, and 28% of all Independents describe their political views as conservative. Suppose an adult in the United States is selected at random.
(a) What is the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative?
P(RC) =
(b) What is the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative?
P(DC) =
(c) Suppose the adult described his views as conservative.
What is the probability (± 0.0001) that he is an Independent?
P(I|C) =
Marketing and Consumer Behavior. Americans drink a lot of coffee, and they put all sorts of extras into their coffee to enhance the drink, including flavor shots and flavored creams. Research data indicates that 62% of all coffee drinkers put creamer in their coffee. Of those people who use creamer, 40% say they would drink more coffee if their preferred flavors were offered.
Suppose a coffee drinker is selected at random
(a) Suppose the coffee drinker uses creamer. What is the probability (± 0.0001) hat he would not drink more even if his preferred flavor were offered?
P(M|C) =
(b) What is the probability (± 0.0001) that the coffee drinker uses creamer and would drink more if his preferred flavor were offered?
P(CM) =
(c) Suppose three coffee drinkers are selected at random. What is the probability (± 0.0001) that exactly one uses creamer?
P(1 of 3 uses creamer) =
8.Public Policy and Political Science. Recent national elections suggest that the political ideology of adults in the United States is very evenly divided. In a USA Today/Gallup survey, 29% were Republicans, 30% were Democrats, and 41% were Independents. In addition, 51% of all Republicans, 16% of all Democrats, and 28% of all Independents describe their political views as conservative. Suppose an adult in the United States is selected at random.
(a) What is the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative?
P(RC) =
(b) What is the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative?
P(DC) =
(c) Suppose the adult described his views as conservative.
What is the probability (± 0.0001) that he is an Independent?
P(I|C) =
10.Marketing and Consumer Behavior. Americans drink a lot of coffee, and they put all sorts of extras into their coffee to enhance the drink, including flavor shots and flavored creams. Research data indicates that 62% of all coffee drinkers put creamer in their coffee. Of those people who use creamer, 40% say they would drink more coffee if their preferred flavors were offered.
Suppose a coffee drinker is selected at random
(a) Suppose the coffee drinker uses creamer. What is the probability (± 0.0001) hat he would not drink more even if his preferred flavor were offered?
P(M|C) =
(b) What is the probability (± 0.0001) that the coffee drinker uses creamer and would drink more if his preferred flavor were offered?
P(CM) =
(c) Suppose three coffee drinkers are selected at random. What is the probability (± 0.0001) that exactly one uses creamer?
P(1 of 3 uses creamer) =
Explanation / Answer
the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative
= P(R intersection C)
= P(R)P(C)
= 0.29(0.51)
= 0.1479
---------------------------------------------
b) the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative
= P(DC) =
= 0.30(0.16)
= 0.048
c) P(I/C) = P(IC)/P(C) = 0.41(0.28)/(0.29)(0.51)+0.30(0.16)+0.41(0.28)
= 0.3695
--------------------------------
a) P(M'/C) = P(M'C)/P(C)
= 60%(62%)/(60%(62%)+(62%)(40%)
= 0.60
b) P(CM) = 0.4(0.62)
=0.248
c) No of coffee drinkers who uses creamer is binomial with p = 0.4 and n =3
P(X=1) = 3C1(0.4)(0.6)2
= 3(0.4)(0.36)
=0.0432
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