a vertical line is drawn through a normal distribution so that 47.5% of the dist

Question

a vertical line is drawn through a normal distribution so that 47.5% of the distribution is located between the line and the mean. The line is drawn @Z equals 1.96 or @Z equals -1.96. Is this true or false a vertical line is drawn through a normal distribution so that 47.5% of the distribution is located between the line and the mean. The line is drawn @Z equals 1.96 or @Z equals -1.96. Is this true or false a vertical line is drawn through a normal distribution so that 47.5% of the distribution is located between the line and the mean. The line is drawn @Z equals 1.96 or @Z equals -1.96. Is this true or false a vertical line is drawn through a normal distribution so that 47.5% of the distribution is located between the line and the mean. The line is drawn @Z equals 1.96 or @Z equals -1.96. Is this true or false

Explanation / Answer

TRUE. Using a table, you will see that the area between the mean and z = 1.96 and the mean z = 0 is 0.475.

Also, as the normal distirbution is symmetric, the area is the same between z = -1.96 and z = 0.

Thus, it is TRUE. [ANSWER, TRUE]

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