The resting heart rates were measured in a sample of women smokers and non smoke

Question

The resting heart rates were measured in a sample of women smokers and non smokers at a state university. There were 14 smokers and 18 non smokers in the sample. Was there a significant difference in the resting heart rates of the two groups? Use alpha .05. (Use a two-tailed test.)

Resting Heart Rates

78, 100, 88, 62, 94, 88, 76, 90, 85, 82, 77, 91, 90, 68

78, 100, 88, 62, 94, 88, 76, 90, 85, 82, 77, 91, 90, 68

Explanation / Answer

Set Up Hypothesis
Null Hypothesis , There Is No-Significance between them Ho: u1 = u2
Alternate Hypothesis, There Is Significance between them - H1: u1 != u2
Test Statistic
X(Mean)=83.5
Standard Deviation(s.d1)=10.376 ; Number(n1)=14
Y(Mean)=72.5
Standard Deviation(s.d2)=10.331; Number(n2)=18
we use Test Statistic (t) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =83.5-72.5/Sqrt((107.66138/14)+(106.72956/18))
to =2.98
| to | =2.98
Critical Value
The Value of |t | with Min (n1-1, n2-1) i.e 13 d.f is 2.16
We got |to| = 2.98066 & | t | = 2.16
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value: Two Tailed ( double the one tail ) - Ha : ( P != 2.9807 ) = 0.011
Hence Value of P0.05 > 0.011,Here we Reject Ho

We have evidence that significant difference in the resting heart rates of the two groups

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