The figure shows a shot-put ring. The shot is tossed from A and lands at B. Usin

Question

The figure shows a shot-put ring. The shot is tossed from A and lands at B. Using modem electronic equipment, the distance of the toss can be measured without the use of measuring tapes. When the shot lands at B an electronic transmitter placed at B sends a signal to a device in the official's booth above the track. The device determines the angles at B and C. At a track meet, the distance from the official's booth to the shot-put ring is 528 feet. If B = 85.4 degree and C = 5.1 degree, determine the length of the toss to the nearest tenth of a foot. The toss was about feet. (Round to the nearest tenth as needed.)

Explanation / Answer

c/sinC = b/sinB

c = 528 x (sin5.1)/(sin85.4) = 47.08786448 feet

in nearest tenth = 50 feet

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