A) Half the range is approximately 3 mm this means that the three times the stan
ID: 340100 • Letter: A
Question
A) Half the range is approximately 3 mm this means that the three times the standard
deviation is approximately 6 mm.
B) If we are interested in the average length we can say that its estimated average
will
have an approximate range of 0.2 mm.
If you make measurements of one million rods and from this calculate one thousand
average values the expected value of the averages
will have this range.
C) If we measure only 500 times we can expect the double standard deviation in the
result.
D) In this measurement the median value is very close to 1003 mm
A) Since we do not see the significant clock shape in the graph (as we do in the Day 1
histogram) a probably explanation is that we have a linear drift in the machine
positioning system.
B) If it was a signific
ant clock shape in the graph as in the Day 1 histogram (but with a
larger range) a probably explanation is that we have a linear drift in the machine
positioning system.
C) Since we do not see the significant clock shape in the graph (as we do in the Day 1
histogram) we can be sure that the problem is just that we need to change the cutting
tool because it is worn out.
D) Due to the shape of the histogram we can assume that the standard deviation is
much lower in Day 2 compared to Day 1
please explain the concept and provide me with the answer
Course code Name Personal number 031 In the workshop you have a machine that cuts steel rods. The machine is simply a cutting tool applied to a robot arm which location is controlled by a closed loop servo system. The nominal lengths of the rods are 1000 mm. In Day 1 and Day 2 you measure the output from the cutting machine by performing 1000 measurements of rods and then you create the following histograms.Explanation / Answer
3.1 - option B because of following reasons:
1. The histogram shows very less standard deviation from the mean of 1000 and maximum values are near to 1003 and minimum values near 997. If we find the range (value - 1000) and then average those ranges over 1000 measurements, it would turn out to be very low value near to 0.2 mm.
2. Expected values of range would not change much going from 1000 to million measurements. (By definition)
3.2 - option A because of following reasons:
1. There appears to be a shift in the mean value produced by the machine and the mean seems to have shifted towards 1005.
2. Also, the standard deviation has increased since the curve shape has become more flatter and wider.
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