Discrete Math Proofs, please help! Put the following statements into order to pr
ID: 3403851 • Letter: D
Question
Discrete Math Proofs, please help!
Put the following statements into order to prove that if 3n+4 is even then n is even. Put N next to the 3 statements that should not be used.
__ Suppose 3n+4 is even.
__ Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even, .
__ Therefore, by definition of odd, 3n+4 is odd.
__ Suppose n is odd.
__ By definition of odd, there exists integer k such that n=2k+1.
__ Then, 3n+4=3(2k+1)+4=6k+7=2(3k+3)+1.
__ Since k is an integer, t =3k+3 is also an integer.
__ Thus, there exists an integer t such that 3n+4=2t+1.
__ By definition of odd, n=2k+1.
__ Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even, .
Explanation / Answer
Since answer is pretty much straight forward , let me just do the numbering :
N .........Suppose 3n+4 is even.
N .........Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even, .
6 .........Therefore, by definition of odd, 3n+4 is odd.
1 ..........Suppose n is odd.
2 ..........By definition of odd, there exists integer k such that n=2k+1.
3 ...........Then, 3n+4=3(2k+1)+4=6k+7=2(3k+3)+1.
4............ Since k is an integer, t =3k+3 is also an integer.
5............ Thus, there exists an integer t such that 3n+4=2t+1.
N .............By definition of odd, n=2k+1.
N .............Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even, .
Hope this Helps!!
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