[1.9] A steel manufacturer produces four sizes of I beams: small, medium, large,
ID: 3404627 • Letter: #
Question
Explanation / Answer
Let, Machine A has been operated for x hours in a week, machine B operated for y hours in a week and machine C operated for z hours in a week.
Since a machine can be operated up to 50 hours per week thus intial condition is given as:
x,y,z <= 50
As given, small beams can be produced by machine A at a rate of 350 feet per hour, by machine B at a rate of 650 feet per hour and by machine C at a rate of 850 feet per hour. So for x, y & h hours of operations of machine A, machine B & Machine C respectively, total Small beam produced is given by:
350x+650y+850z
Also the requirement of small size beam per week is 12000 feet, so the equation for small beam is given by:
350x+650y+850z >=12000
Similarly for medium beam, equation is given by
250x+200y+700z>=6000
for large beam, equation is given by
200x+350y+600z>=5000
and for extra large beam, the equation is given by
125x+200y+325z>=7000
For every operation, to maximize the profit the operating cost is minimized. In the above problem, hourly operating cost for machine A is $30, for machine B is $50 and for machine C is $80. Thus the total operating cost for the week is given as,
P = 30x+50y+80z
So the LPP is as below:
Minimize P = 30x+50y+80z
Constraints:
350x+650y+850z >=12000
250x+200y+700z>=6000
200x+350y+600z>=5000
125x+200y+325z>=7000
and x,y,z <= 50
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