The distance d (in ft) required to stop a car that was traveling a speed v (in m

Question

The distance d (in ft) required to stop a car that was traveling a speed v (in mph) before the breaks were applied depends of the amount of friction between the tires and the road and the drivers reaction time. After an accident, a legal team fired an engineer firm to collect data for the stretch of the road where the accident occured. Based on the data, stopping distance is given by d =0.05v2+5.5v

Determine the distance reqired to a stop a car going 30mph. Round the nearst foot.

It wil take a distance of what ft. to stop a car going 30mph.

Explanation / Answer

The data, stopping distance is given by d =0.05v2+5.5v

Speed (v) =  30mph

Change mph into ft per sec

so that 1 Miles per Hour = 1.466667 Foot per Second

therefor for 30 mph = 30*1.4666

   = 43.999

~= 44 foot per sec

putting this value we get

d =0.05v2+5.5v

d =0.05(44)2+5.5(44)

d = 338.8 foot

distance of 338.8 ft. to stop a car going 30mph.

Answer

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