There is a question in chegg\'s Technical Mathematics 6e Book, chapter 6.3 quest

Question

There is a question in chegg's Technical Mathematics 6e Book, chapter 6.3 question#7 that is different from my text book? Can this be fixed or corrected? posting a picture of real math problem.

Chapter 6 Geometry 7. What is the cost of plastering the walls and ceiling of a room 40 ft long, 36 fr 22 s8.50 per square yard, 1375 ft for doors, windows, and baseboard? 184 ft wide. 8. What will cost to cement the floor of a cellar 25.3 ft long and 9. at 53.50 per square foot? and 48in. Find the cost ofiining a topless rectangular tank 68 in- long, 54 in. wide. deep with zinc, weighing 5.21b per square foot, at $1.55 per pound installed. 10, A parcel of land lies between two parallel streets, Fig. 6 60. How many acres will remain in the parcel after the strip shown is taken for a new street? (i acre 43,560 ft 350 ft sect is th divi all

Explanation / Answer

7.

Thats like taking out surface area of walls and subtractign door+window +bb area
= 2(40*36+22*36+40*22) - 1375
= 6224 -1375
= 4849 ft^2

Per sqft cost is 8.5 per square yard
1 ft is 1/3 yard
9sqft is therefore area of 1 yd^2
So, 9ft^2 takes $8.5

So, 1ft^2 takes $8.5/9

Now, total cost= 4849 * cost per square yard
= 4849 *(8.5/9)
= $4579.611

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