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8. A one-tailed hypothesis test for a repeated-measures design Aa Aa A researche

ID: 3450749 • Letter: 8

Question

8. A one-tailed hypothesis test for a repeated-measures design Aa Aa A researcher is interested in whether using your finger to follow the words you are reading increases reading speed He has students complete a reading speed test, first without using their fingers to follow the words, and then again while using their fingers to follow the words. In the beginning of the study, a randomly selected group of 64 students scored an average of 256 words per minute on the reading speed test. Since the sample size is larger than 30, the researcher can assume that the sampling distribution of Mo is normal. He plans to use a repeated-measures t-test. The researcher identifies the null and alternative hypotheses as: Use the Distributions tool to find the critical region(s) for = .05. The critical t-score, which is the value for t-scores that separates the tail(s) from the main body of the distribution and forms the critical region(s), is consider whether this is a one-tailed or two-tailed test.) (Hint: Remember to set the degrees of freedom on the tool and to Degrees of Freedom 75 5000 5000 .5000 2500 2500 3.0 2.0 0.0 0.678 0.000 0.678 1.0 2.0 3.0 4.0 In the trial where they used their fingers while they read, the students scored an average of 9 words per minute higher than before they began using their fingers while they read. The standard deviation of the difference scores was s=29 To calculate the t statistic, you must first calculate the estimated standard error. The estimated standard error is . (Note: For best results, retain at least 4 decimal places from your calculation of the estimated standard error for use in calculating the t statistic.) Calculate the t statistic. The t statistic is Use the tool to evaluate the null hypothesis. The t statistic hypothesis test. Therefore, the null hypothesis is your finger to follow the words increases reading speed in the critical region for a one-tailed ·The researcher- conclude that using

Explanation / Answer

Null Hypothesis - H0: D = 0.

Alternative Hypothesis - H1: D 0.

The critical t-score for one-sample t(63) = 1.9983, p = 0.05 (Derived from the t-table)

The standard error is 3.625 (Derived by dividing the standard deviation (29) with square root of the sample size (64))

Please post the other questions separately as we are supposed to answer just one question or or four sub parts of a question.

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