Hardy-Weinburg questions Please help with the numbers. I understand the concept,

Question

Hardy-Weinburg questions

Please help with the numbers. I understand the concept, but need the numbers ><

1) The deleterious recessive allele exists at a proportion of 0.01. In an offspring with randomly chosen parents, what is the probability that the offpsring will be homozygous for the deleterious recessive allele [q]?

2) A Generation of Indiviuals in a Population: A1A1   A1A1   A1A2   A1A2 A2A2

So the allels present in the generation are : A1 A1 A1 A1 A1 A2  A1 A2  A2  A2  A2

a. What is the probability that Allele A1 eventually becomes fixed in the population?

b. What is the probability that Allele A1 eventually disappears from the population?

c. What is the probability that Allele A2 eventually becomes fixed in the population?

d. What is the probability that Allele A2 eventually disappears from the population?

A1 = p

A2 = q

Explanation / Answer

1) probability that offspring will be homozygous for deleterious allele [q] = [q]2 (taking square) thus, q= 0.1.

2) There are 5 individuals in the population using hardy weinberg rules we can find value of p, q and 2pq i.e found to be q= 0.44 & p=0.56 and 2pq=0.492

a. allele A1 getting fixed (only homozygous included) = p=0.56 i.e. 56% probability of allele A1 getting fixed

b. allele A1 being lost is nothing but the sum of 2pq and q. which is 0.49+0.44= 0.93 i.e 93%

c. allele A2 getting fixed =q=0.44 i.e. 44% probability of being fixed.

d. -

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