Hardy-Weinberg questions.... Genotypes of leopard frogs from a population in cen

Question

Hardy-Weinberg questions....

Genotypes of leopard frogs from a population in central Kansas were determined for a locus (M) that encodes the enzyme malate dehydrogenase. The following #'s of genotypes were observed: Total sample =107

a. Calculate the allelic frequencies for this population.

Alleles = M1 and M2

For M1:

I did ((2*20) +45)/(107*2) = 0.3971 -->1 sig fig = 0.4

For M2:

((2*42) +45)/(107*2) = 0.6028 -->2 sig fig = 0.60

This makes sense to me but I'm not sure if this is correct??

b. What are the actual genotypic frequencies in the above populations? What would the expected numbers of genotypes be if the population were in Hardy- Weinberg equilibrium?

Actual genotypic frequencies:

M1M1 = 20/107 = 0.1869 --> 0.2

M1M2 = 45/107 = 0.42056 -->0.42

M2M2 = 42/107 = 0.3925 --> 0.39

For population in Hardy- Weinberg equilibrium:

M1M1 = p2 = (0.186)2 = 0.034 x 107 = 3.73 --> 4 frogs with M1M1

M1M2 = 2(pq) = (0.420) = 0.841 x 107 = 89.99 --> 90 frogs with M1M2

   M2M2 = q2 = (0.392)2 = 0.154 x 107 = 16.4 --> 16 frogs with M1M1

This equals 110....due to rounding but is all of this correct?

Explanation / Answer

yes

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