Help Hardy Weinberg I know the answers, but I am unsure how they are calculated,

Question

Help Hardy Weinberg

I know the answers, but I am unsure how they are calculated, could someone please show me how to work these two?

15) If, on average, 46% of the loci in a species' gene pool are heterozygous, then the average homozygosity of the species should be _____.

A) 23%

B) 46%

C) 54%

D) 92%

16) Suppose 64% of a remote mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be heterozygous for this trait?

A) 16%

B) 32%

C) 40%

D) 48%

Explanation / Answer

15) They have to be heterozygous or homoozygous...If 46% of the loci are heterozygous the remaining have to be homozygous....giving you...

(100-46=54) 54%

16) If 64% can, 36% can't. (100% - 64% = 36%)

q^2 = 0.36
q = 0.6.

p = 1 - 0.6 = 0.4

Heterozygotes = 2pq = 2 (0.4) (0.6) = .48

48% of the population.

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