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Table 2. Molarity and osmolarity of various NaCI solutions and the reaction of s

ID: 3508332 • Letter: T

Question

Table 2. Molarity and osmolarity of various NaCI solutions and the reaction of sheep erythro Tube NaCI MolarityOsmolarity Appearance of RBCS (g/dL) (M (mOsM) Solution Tonicity 10.0 3.500 0.850 0.650 0.200 0.145 290.0 Normal* Units: 10 dl-1; Appearance: normal, crenated, enlarged, hemolyzed; Tonicity: Iso-, hypo-, hypertonic compared with normal blood. (Normal osmolarity of blood is 290-300 mOsM.) Report molarity (M) to 3 places to the right of the decimal point and osmolarity (mOsM) 1 place to the right. Do not round up before calculating in the final units. 28

Explanation / Answer

Explanation of 3 answer

1. Calculation of Molarity. (You need a periodic tabel and calculator).

Molecular mass of NaCl = atomic mass of Na + atomic mass of Cl.

= 22.99×1 + 35.453 (multiply by 1 as each molecule of NaCl has 1 Na and 1Cl atom).

= 58.443

This molecular mass can be converted to Molar mass as 58.443 g of NaCl is equal to 1 Mole (according to mole Concept).

Molar mass of NaCl = 58.443 g/mol

Apply unitry method to calculate the numbers of mole in given ie 0.850g of NaCl = 0.850/58.443 = 0.0145 g/mol.

To calculate Molarity divide it by Liters of solution, so as 1Liter = 10dl ( or 1dl = 0.1 L , as the concentration of NaCl in solution is 0.850g/dl).

Therefore Molarity = 0.0145/0.1 = 0.145 M.

2. Osmolarity = total Contribution of molecule to Osmolarity. As each molecule of NaCl dissociate into 1 Na+ and 1 Cl - ion, ie number of dissociate ion, therefore the effective Osmolarity will be Molarity × 2 ( as total dissociated ions are 2)

Therefore osmolarity of 0.145 M solution = 0.145 × 2 = 0.29 OsM

To convert it into mOsM multiply it by 1000 = 0.29 × 1000 = 290 m OsM.

Appearance of RBC depends on Osmolarity, if Hypertonic (ie more concentrated) then RBC wll shrink. And if Hyposomolar (ie less concentrated than Normal) tjen RBC will swell up.

Best of luck for solving the rest.

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