What will be the output of the program? public class RTExcept { public static vo

Question

 
What will be the output of the program?

public class RTExcept  {     public static void throwit ()      {         System.out.print("throwit ");         throw new RuntimeException();     }     public static void main(String [] args)      {         try          {             System.out.print("hello ");             throwit();         }         catch (Exception re )          {             System.out.print("caught ");         }         finally          {             System.out.print("finally ");         }         System.out.println("after ");     } } 

  
What will be the output of the program?

public class RTExcept   {      public static void throwit ()       {          System.out.print("throwit ");          throw new RuntimeException();      }      public static void main(String [] args)       {          try           {              System.out.print("hello ");              throwit();          }          catch (Exception re )           {              System.out.print("caught ");          }          finally           {              System.out.print("finally ");          }          System.out.println("after ");      }  }  

Explanation / Answer

output should be : "   hello throwit caught finally after "

The main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.

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