Consider a processor with a delayed branch that has three delay slots. Three com
ID: 3541158 • Letter: C
Question
Consider a processor with a delayed branch that has three delay slots. Three compilers compiler A, compiler B and
compiler C, could run on this processor. Compiler A can fill the first delay slot 60% of the time and the second
delay slot 40% of the time and the third delay slot 20% of the time (filling delay slot is independent). Compiler B
can fully fill all the three delay slots. Compiler C leaves all the slots empty. Assuming that branches account for
20% of all instructions and arithmetic/logic operations for the remaining 80% of the instructions for any program,
what is the improvement of CPI with compiler B compared to CPI with compiler A and compared to CPI with
compiler C? Assume that CPI of arithmetic/logic operations is 1.
Explanation / Answer
Compiler B=(1-(1/48000))*20/100
Compiler C=((0.1999+109/120))-1
0.3082=30.82%
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