Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected

Question

Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a link of R=2 Mbps, and there are 4 routers between A and B. Suppose the propagation speed over the link is 2.5*108 meters/sec, average queueing time is 2ms,

processing 3ms on each router. Consider sending a file of 800,000 bits from Host A to Host B. Suppose the file is sent continuously as one large message. How much time for B to receive the whole file after A sent out the first bit?( A little bit explanations please, formulas etc)

Explanation / Answer

time to just transfer the data = 800000 / (1024*1024*2) sec = 381 ms

time taken to reach data with speed 2.5*10^8 m/s = 20000*1000 / 2.5*10^8 sec = 80 ms

time taken for queueing and processing by the 4 routers = 4*5 ms = 20 ms

the total time taken is the sum of the above time calculated

= 381+80+20 = 481 milliseconds

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