Whenever a computer is idle, we can either put it in stand by (where DRAM is sti

Question

Whenever a computer is idle, we can either put it in stand by (where DRAM is still active) or we can let it hibernate. Assume that, to hibernate, we have to copy just the contents of DRAM to a nonvolatile medium such as Flash. If reading or writing a cacheline of size 64 bytes to Flash requires 2.56 ?J and DRAM requires 0.5 nJ, and if idle power consumption for DRAM is 1.6 W (for 8 GB), how long should a system be idle to benefit from hibernating? Assume a main memory of size 8 GB Whenever a computer is idle, we can either put it in stand by (where DRAM is still active) or we can let it hibernate. Assume that, to hibernate, we have to copy just the contents of DRAM to a nonvolatile medium such as Flash. If reading or writing a cacheline of size 64 bytes to Flash requires 2.56 ?J and DRAM requires 0.5 nJ, and if idle power consumption for DRAM is 1.6 W (for 8 GB), how long should a system be idle to benefit from hibernating? Assume a main memory of size 8 GB

Explanation / Answer

Total DRAM memory = 1.6 * 8 * 10^9 Bytes J/seconds = 12.8*10^9 J/s ---1

Total energy required to read or write cache-line to Flash and DRAM = 2*64*( 2.56 *10^-6+0.5 *10^-9) J = 3.277*10^-4 J---2

The time a system will be idle is 2/1 = 2.56*10^-14 seconds

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