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You have been assigned the Class B network 219.170.0.0. The default (Classful) s

ID: 3556058 • Letter: Y

Question

You have been assigned the Class B network 219.170.0.0.
The default (Classful) subnet mask for this network is:   __________________________________
Using the default subnet mask for this network,
can you support how many hosts or clients?       __________________________________
Subnet this network into 2 subnets and provide the following information:
What is the new subnet mask for this network?       __________________________________
List the two subnets (Network IDs):
__________________________________       __________________________________
How many hosts can be supported by each subnet?   __________________________________
How many total hosts can be supported?       __________________________________
List the address range each subnet and the directed broadcast address:
Subnet Identifier   Valid Host Range   Broadcast Address for Subnet
      
      

Given IP 173.194.46.7 and mask 255.255.224.0
Specify the subnet that contains this IP host address and the range of addresses within this subnet:
Subnet Containing IP   Start of Range - End of Range
  

Explanation / Answer

PART - I

Since it is Class B address Subnet Mask will be : 255.255.0.0

No of Hosts or Clients it supports - 216

After dividing into 2 Subnets , Subnet Mask will be - 219.170.128.0

Network IDs of 2 Subnets - 1) 219.170.0.0 2) 219.170.128.0

No of Hosts supported by each Subnet - 215

Total no of Hosts - 215 + 215 = 216

For Subnet 1 - Subnet ID (Network ID) : 219.170.0.0

Valid Host Range : 219.170.0.1 to 219.170.127.254

Broadcast Address : 219.170.127.255

For Subnet 2 - Subnet ID (Network ID) : 219.170.128.0

Valid Host Range : 219.170.128.1 to 219.170.255.254

Broadcast Address : 219.170.255.255

PART - II

Given IP - 173.194.46.7 and Mask - 255.255.224.0

Subnet contains this Host - 173.194.32.0

Range of this Subnet - 173.194.32.1 to 173.194.63.255

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