You have been assigned the Class B network 219.170.0.0. The default (Classful) s
ID: 3556059 • Letter: Y
Question
You have been assigned the Class B network 219.170.0.0.
The default (Classful) subnet mask for this network is: __________________________________
Using the default subnet mask for this network,
can you support how many hosts or clients? __________________________________
Subnet this network into 2 subnets and provide the following information:
What is the new subnet mask for this network? __________________________________
List the two subnets (Network IDs):
__________________________________ __________________________________
How many hosts can be supported by each subnet? __________________________________
How many total hosts can be supported? __________________________________
List the address range each subnet and the directed broadcast address:
Subnet Identifier Valid Host Range Broadcast Address for Subnet
Given IP 173.194.46.7 and mask 255.255.224.0
Specify the subnet that contains this IP host address and the range of addresses within this subnet:
Subnet Containing IP Start of Range - End of Range
Explanation / Answer
As it is a class-B address deafult subnet mask is 255.255.0.0
no of clients or hosts are 2^16
new subnet mask is 255.255.128.0
new subnet(Network ID's) 255.170.0.0 255.170.128.0
no of hosts supported by each subnet is 2^15
Total no hosts supported = 2^15 + 2^15 = 2^16
Subnet-1:
subnet identifier(Network id = 255.170.0.0)
valid host range 255.170.0.1 to 255.170.127.254
broadcast address is 255.170.127.255
Subnet-2:
subnet identifier(Network id = 255.170.128.0)
valid host range 255.170.128.1 to 255.170.255.254
broadcast address is 255.170.255.255
PART-2:
Given IP is 173.194.46.7
mask is 255.255.224.0
subnet address is 173.194.32.0
Range os address in this subnet is 173.194.32.1 to 173.194.63.254
broadcast address in this subnet is 173.194.63.255
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