What is wrong with the following switch statement? int ans; cout \"Type y for ye

Question

What is wrong with the following switch statement? int ans; cout "Type y for yes or n for no "; cin ans; switch (ans) { case 'y': caae 'Y': cout "You said yes "; break; case 'n': case 'N': cout "You said no "; break; default: cout "Invalid answer "; } //End switch There are no break statements on two of the cases ans is an integer data type Nothing break; is illegal syntax What is wrong with the following statement? cout "Hello to everyone " cout should be count It is missing a " It is missing a semicolon It is missing a ( should be The concatenation operator is ______. & + && An algorithm is______. the part of the computer that does the processing the inputs and outputs of a program a complete computer program a finite set of steps to solve a problem

Explanation / Answer

1.C nothing

2 C it is missing a semicolon

3. D, +

4. D, a finite set of steps to solve a problem

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