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PLease help with these flip flops You are required to design a MOD 75 counter. W

ID: 3566371 • Letter: P

Question

PLease help with these flip flops

You are required to design a MOD 75 counter. What is the minimum number of flip-flops needed to build the counter? Space for working Answer: a) Consider the counter circuit above. This circuit is which of the following: b) The counter value changes when: i) Synchronous MOD 4 up-counter ii) Asynchronous MOD 32 up-counter iii) Asynchronous MOD 32 down-counter iv) Synchronous MOD 16 down-counter I) Rising edge of CLK occurs ii) Falling edge of CLK occurs iii) On both rising and falling edges of CLK iv) CLJ is 1. Answer: Answer:

Explanation / Answer

1) minimum no of flip flops= ceil(log2(mod))

mod=75;

ceil(log2(mod))=7

minimum no of flip flops=7

2)a)clock of subsequent stage is derived from previous stage. So asynchronous counter

since it is rsising edge ff and 5-bit, it MOD 32-down counter

b)rising edge of clock as a arrow is shown at clock input

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