QUESTION 3 At a car rental kiosk at a busy airport, customers arrive and wait in

Question

QUESTION 3 At a car rental kiosk at a busy airport, customers arrive and wait in a common line for the first available of two sales agents. The agents can serve a customer in an average of 2.5 minutes (assume negative exponential distribution). On average, 21 customers per hour will arrive to be served (assume Poisson arrivals). What is the average time a customer spends waiting in line before being served (in minutes)? a. 0.6 mins b. 3.1 mins ° C. 17.5 mins d. 35.6 mins QUESTION 4 sales agents. The agents can servea customer in an average of 2.5 minutes (assume negative exponential distribution). On average, 21 customers per hour will arrive to be served (assume Poisson arrivals). However, on this day, assume that one of the computers is not working, and so the two sales agents work together helping one customer at a time. The new average service time per customer is now 1.9 minutes. What is the average time a customer spends at the kiosk (includes waiting and being served, in minutes, rounded to two decimals)? a. 2.13 mins b. 3.09 mins c. 5.67 mins Od. 7.22 mins

Explanation / Answer

3)

Arrival rate (A) = 21 per hour

Service rate (S) = 2.5 minutes or 60/2.5 = 24 per hour

Average waiting time = A/(S*(S-A)) = 21/(24*(24-21)) = 0.29 hours or 0.29*60 = 17.50 minutes

Ans: C

4) Arrival rate (A) = 21 per hour

Service rate (S) = 1.9 minutes or 60/1.9 = 31.58 per hour

Average waiting time = A/(S*(S-A)) = 21/(31.58*(31.58-21)) = 0.29 hours or 0.29*60 = 3.77 minutes

Service time = 1.9 minutes

Total = 3.77+1.9 = 5.67 minutes

Ans: C

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