My question is only part (b), but I write part( a) down, to understand my questi

Question

My question is only part (b), but I write part( a) down, to understand my question properly.

a, A physiotherapist is interested in the current physical fitness of orienteers. He intends on investigating this by assessing the fitness of a sample of a few orienteers .

Suppose that the physiotherapist decides that he can afford to assess approximately one eighteenth of the orienteers who were at the event.

Select by hand a suitable sample for this physiotherapist, using systematic random sampling. Any random numbers you require should be obtained from the random number table given in the appendix, starting at row 61.

MY QUESTION :

b, At the event, each orienteer completed one of seven different courses. Before the id numbers for the orienteers were allocated sequentially, the orienteers were grouped by which course they did.

Explain why the sample you obtained in part (a) is similar to a stratified sample. In what way is it different??

Thanks for help !!

Explanation / Answer

Hi..

In part A we used a systematic sampling technique to choose our sample. After assigning the participants a number and listing them sequentially, we then chose from a random starting point every eighteenth participant.

In a stratified sample, the population is grouped in some logical way. In a large corporation, you might group by job description, etc... Here the participants are grouped by course number.

If we had used a stratified sampling technique, we would have randomly chosen individuals from each strata (group.)

In our actual process, we selected members from a sequential list by choosing every eighteenth one from a random starting point. Since the participants were grouped before being listed sequentially, the systematic sample pulls equally from each of the strata, thus the sample is similar to a stratified sample.

In a stratified sample we could take ddifferent numbers of individuals from the different groups, while here we took equal numbers from each group...

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