Match the IP address and mask pairs with their types. IP Address 202.0.18.63 usi
ID: 3579272 • Letter: M
Question
Match the IP address and mask pairs with their types.
IP Address 202.0.18.63 using mask 255.255.255.192
IP address 123.45.67.89 using mask 255.255.255.248
IP Address 172.16.37.13 using mask 255.255.252.0
IP Address 10.3.0.34 using mask 255.255.255.240
A host on the 9th useable subnet.
A subnet broadcast address.
A subnet's network address.
First useable host
-A.B.C.D.IP Address 202.0.18.63 using mask 255.255.255.192
IP address 123.45.67.89 using mask 255.255.255.248
IP Address 172.16.37.13 using mask 255.255.252.0
IP Address 10.3.0.34 using mask 255.255.255.240
A.A host on the 9th useable subnet.
B.A subnet broadcast address.
C.A subnet's network address.
D.First useable host
Explanation / Answer
IP Address 202.0.18.63 using mask 255.255.255.192 will give the address: 202.0.18.0/26. Therefore, is a B. A subnet broadcast address.
IP address 123.45.67.89 using mask 255.255.255.248 will give the address:123.45.67.88/29. Therefore, is a D. First useable host.
IP address 172.16.37.13 using mask 255.255.252.0 will give the address: 172.16.36.0/22. Therefore, the answer is A. A host on the 9th useable subnet.
IP address 10.3.0.34 using mask 255.255.255.240 will give the address:10.3.0.32/28, and therefore, 10.3.0.34 is actually, the second usable IP. (May be the answer is wrong, or it should be choice C)
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