Take Test: 2. Chapter 9 Quiz - Click Here Question 1 Structure of the ORDERS tab
ID: 3580149 • Letter: T
Question
Take Test: 2. Chapter 9 Quiz - Click Here
Question 1
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following queries will display data from both the ORDERS and CUSTOMERS tables?
a.
SELECT lastname, firstname, order#
FROM orders, customers
WHERE orders.customer# = customers.customer#;
b.
SELECT lastname, firstname, order#
FROM orders NATURAL JOIN customers;
c.
SELECT * FROM orders, customers;
d.
all of the above
0.1 points
Question 2
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which SQL statement will return the same results as the following SQL statement?
SELECT * FROM orders, customers;
a.
SELECT * FROM orders, customers
WHERE orders.customer# > customers.customer#;
b.
SELECT * FROM orders, customers
WHERE orders.customer# = customers.customer#;
c.
SELECT * FROM orders CROSS JOIN customers;
d.
SELECT * FROM o orders , c customers
WHERE o.customer# = c.customer#;
0.1 points
Question 3
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following queries will return the same results as the following SQL statement?
SELECT c.customer#, lastname, firstname, order#
FROM customers c, orders o
WHERE c.customer# = o.customer#;
a.
SELECT customer#, lastname, firstname, order#
FROM customers NATURAL JOIN orders;
b.
SELECT c.customer#, lastname, firstname, order#
FROM customers c, orders o;
c.
SELECT customer#, lastname, firstname, order#
FROM customers JOIN orders USING (customer#);
d.
both a and b
0.1 points
Question 4
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following SQL statements will return the names of all customers who placed an order on April 12, 2003?
a.
SELECT lastname, firstname
FROM customers
WHERE orderdate = '12-APR-03';
b.
SELECT lastname, firstname
FROM customers NATURAL JOIN orders
WHERE orderdate = '12-APR-03';
c.
both a and b
d.
SELECT lastname, firstname
FROM customers JOIN orders ON (customer#)
WHERE orderdate = '12-APR-03';
0.1 points
Question 5
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following SQL statements will list the name of each customer stored in the CUSTOMERS table, and, if the customer has placed an order that is contained in the ORDERS table, the order# of any order each customer has placed?
a.
SELECT lastname, firstname, order#
FROM customers c LEFT OUTER JOIN orders o
ON c.customer# = o.customer#;
b.
SELECT lastname, firstname, order#
FROM customers RIGHT OUTER JOIN orders;
c.
SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders;
d.
SELECT lastname, firstname, order#
FROM customers JOIN orders USING (customer#);
0.1 points
Question 6
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following SQL statements will list the name of each customer stored in the CUSTOMERS table, and, if the customer has placed an order that is contained in the ORDERS table, the order# of any order each customer has placed?
a.
SELECT lastname, firstname, order#
FROM customers, orders
WHERE orders.customer# = customers.customer# (+);
b.
SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NOT NULL;
c.
SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NULL;
d.
SELECT lastname, firstname, order#
FROM customers, orders
WHERE orders.customer# (+) = customers.customer#;
0.1 points
Question 7
Structure of the ORDERS table
Structure of the CUSTOMERS table
Which of the following SQL statements will display all customers who have not recently placed an order?
a.
SELECT customer# FROM customers
UNION
SELECT customer# FROM orders;
b.
SELECT customer# FROM orders
MINUS
SELECT customer# FROM customers;
c.
SELECT customer# FROM orders
INTERSECT
SELECT customer# FROM customers;
d.
SELECT customer# FROM customers
MINUS
SELECT customer# FROM orders;
0.1 points
Question 8
A join based upon a column from each table containing equivalent data is known as a(n) ____.
a.
equality join
b.
outer join
c.
inequality join
d.
all of the above
0.1 points
Question 9
A table alias can consist of a maximum of ____ characters.
a.
12
b.
225
c.
30
d.
255
0.1 points
Question 10
Which of the following can only be used to link tables that have a common column?
a.
FULL OUTER JOIN
b.
JOIN...ON
c.
CROSS JOIN
d.
NATURAL JOIN
0.1 points
Question 11
Which of the following keywords can be used to join two tables that do not contain a commonly named and defined column?
a.
JOIN...USING
b.
NATURAL JOIN
c.
JOIN...ON
d.
none of the above
0.1 points
Question 12
Which of the following types of joins refers to joining a table to itself?
a.
Cartesian join
b.
equality join
c.
self-join
d.
outer join
0.1 points
Question 13
Structure of the BOOKS table
Structure of the PUBLISHER table
Which of the following SQL statements will display the title of each book in the BOOKS table and the name of its publisher?
a.
SELECT title, name
FROM publisher NATURAL JOIN books;
b.
SELECT title, name
FROM publisher, books;
c.
both b and c
d.
SELECT title, name
FROM publisher, books
WHERE p.pubid = b.pubid;
0.1 points
Question 14
Structure of the BOOKS table
Structure of the PUBLISHER table
Which of the following SQL statements will display the publisher name, book title, and retail price of all books that cost more than $35.95?
a.
SELECT name, title, retail
FROM books NATURAL JOIN publisher
WHERE cost > 35.95;
b.
SELECT p.name, b.title, b.retail
FROM books b NATURAL JOIN publisher p
WHERE b.cost > 35.95;
c.
SELECT name, title, retail
FROM books, publisher
WHERE cost > 35.95;
d.
none of the above
0.1 points
Question 15
Structure of the BOOKS table
Structure of the PUBLISHER table
Which of the following will display the title, publication date, and publisher name of each book in the BUSINESS category?
a.
SELECT title, pubdate, name
FROM publisher CROSS JOIN books USING (pubid)
WHERE category = 'BUSINESS';
b.
SELECT title, pubdate, name
FROM publisher JOIN books ON (pubid)
WHERE category = 'BUSINESS';
c.
SELECT title, pubdate, name
FROM publisher OUTER JOIN books USING (pubid)
WHERE category = 'BUSINESS';
d.
SELECT title, pubdate, name
FROM publisher JOIN books USING (pubid)
WHERE category = 'BUSINESS';
a.
SELECT lastname, firstname, order#
FROM orders, customers
WHERE orders.customer# = customers.customer#;
b.
SELECT lastname, firstname, order#
FROM orders NATURAL JOIN customers;
c.
SELECT * FROM orders, customers;
d.
all of the above
Explanation / Answer
1) Answer: d
2)Answer: c
3)Answer: d
4)Answer: b
5)Answer: a
6)Answer: a
7)Answer: d
8)Answer: a
9)Answer: c
10)Answer: a
11)Answer: b
12)Answer: c
13)Answer: a
14)Answer: b
15) Answer: c
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