Write a program sum of the two numbers in hexadecimal. that reads in two hexadec

Question

Write a program sum of the two numbers in hexadecimal. that reads in two hexadecimal numbers from a file, hex.ext, and prints out the From Wikipedia: "In mathematics and computer science, hexadec hex) is a positional numeral system with a radix, or base, of 16. It uses sixteen distinct symbols, most often the symbols 0-9 to represent val and A, B, C, D,E, F (or alternatively a-f) ues zero to nine, to represent values ten to fifteen AF3 is equal, in decimal, to THE SUM OF: For example, the hexadecimal number 2 (2x 16') + (10 x 162) + (15 x 16') + (3x ie) og 10,995." For example, if the file contains: 45AF 12B3 ...and then your program will output (if you output the result in decimal): sten (Haxt) The decimal sum of 45AF and 12B3 is 22626. (To check your results, you can go to a hexadecimal calculator on the Web. For example, http://www.csgnetwork.com/hexaddsubcalc.html) To solve this problem: Read the hexadecimal numbers as character arrays Convert the charac character array as a parameter, and returns an integer) Add the numbers to get a decimal sum EXTRA CREDIT: convert the sum to hexadecimal (by calling a function that fills a) b) ter arrays to numbers (by calling a function that takes the c) d) a character array) PART II Assume that your file has an unknown number of hexadecimals. Modify/ Enhance/Change the program so that it prints the sum of all the numbers in the file.

Explanation / Answer

Please see the following code.

Answer:

   

#include<stdio.h>

#include<conio.h>

#include<string.h>

#include <stdlib.h>     

int main()

{

             int i ;

               int c[30];

          int x=0,y=1,j=0,k=0;

         char s[30],q[30];

        printf("Convert from hex to Dec");

         printf("Enter 1st hex number");

        scanf("%s",s);

        printf("Enter 2nd hex number");

        scanf("%s",q);

        printf("Decimal Equivalent of hex=");

         printf("Sum = ");

         for(i=0;s[i]!=NULL; i++)

         {

          switch(s[i])

           {

            case '0':

             c[i]=0;

             break;

            case '1':

             c[i]=1;

             break;

            case '2':

             c[i]=2;

             break;

            case '3':

             c[i]=3;

             break;

            case '4':

             c[i]=4;

             break;

            case '5':

             c[i]=5;

             break;

            case '6':

             c[i]=6;

             break;

            case '7':

             c[i]=7;

             break;

            case '8':

             c[i]=8;

             break;

            case '9':

             c[i]=9;

             break;

            case 'a':

            case 'A':

             c[i]=10;

             break;

            case 'b':

            case 'B':

             c[i]=11;

             break;

            case 'c':

            case 'C':

             c[i]=12;

             break;

            case 'd':

            case 'D':

             c[i]=13;

             break;

            case 'e':

            case 'E':

             c[i]=14;

             break;

            case 'f':

            case 'F':

             c[i]=15;

             break;

            default:

             printf(" Not a hexadecimal number");

             break;

}

         }

         i--;

         for(;i>=0;i--)

         {

          x=x+c[i]*y;

          y=y*16;

          j=j+c[i]*y;

          k=(x+j)/8.5;

         }

printf("%d ",k);

printf("%d ",(x+j));

getch();

}

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