5) multiple floating points aligned by the decimal point in C programming, only
ID: 3589551 • Letter: 5
Question
5) multiple floating points aligned by the decimal point in C programming, only allow to use %d, %c for printf, use if, if-else and while loop.
a)read in x number of floating points, where x is the positive integer(assume the number is less than 20). You can assume that the user will enter x floating points separated by spaces.
b)once all of the x floating points have been entered, they should be printed out with decimal points aligned.
For input 45 . 678, 4567 . 8, 4 . 5678. -12, 0 . 3456789, 456. 78. the output will be: 45.678 4567·8 4.5678 -12.0 0.3456789 456.78Explanation / Answer
Note: as i compiled in dev c++ the ouput is shown below according to requirement . as iam taking values in float array if you give more than 3 values after the decimal it will display three vaulues only .
#include<stdio.h>
#include<math.h>
int count;
int main()
{
char buf[20];
int val,i=0,k=0; //declaring the variables
getval:printf("enter the number of values you want:"); // label named getval and follwoing print statement
scanf("%d",&val); //scanning the value from user
float dec[val];
if( val>=20) // as you said the user canot enter greater than 20
{
printf("please enter the values less than 20 ");
goto getval;
}
printf("enter the decimal values :");
while( val>=0) // as you while loop is used
{
scanf("%f",&dec[i]); //storing the elements in array
i++; // incrementing value of i
val--; //decrementing value of val
}
int n = sizeof(dec);
printf("the output values are :");
for (i=0 ; i<=n/sizeof(int);i++)
{
int dot=0;
int j;
gcvt(dec[i],6,buf); // this is standard function which converts float to string
for(j=0;j<=sizeof(buf);j++)
{
if(buf[j]!='.'&& dot!=1 )
{
count++;
}
if(buf[j]=='.')
{
dot=1;
}
}
printf("%s ",buf);
count=0;
}
}
output:
enter the number of values you want:3
enter the decimal values :10.986 1.3 1098.8 -12
the output values are :
10.986
1.3
1098.8
-12.
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